16(c)^2=196

Solution for 16(c)^2=196 equation:

16(c)^2=196

We move all terms to the left:

16(c)^2-(196)=0

a = 16; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·16·(-196)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*16}=\frac{-112}{32}
=-3+1/2
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*16}=\frac{112}{32}
=3+1/2
$